Prove the identity \(\frac{1}{2\csc 2x}=\cos^2 x \tan x\) Choose the sequence of steps below that verifies the identity A) \(\cos^2 x \tan x =\cos^2 x \frac{\sin xMaking assumptions about where parentheses should be, cosx/ (secx 1) = (secx 1)/ (secx 1) cosx/ (secx 1) = (secx cosx cosx)/ (sec^2x 1) = (1 cosx)/tan^2x = (cosx 1)/tan^2x (secx1) (cosx1)=sin^2x/cosx 1/cosxcosx=sin^2x/cosxAnswer to Prove each of the following identities tan x cos x/1 sin x = 1/cos x tan^2 x 1 = sec^2 x 1/1 sin x 1/1 sin Skip Navigation Chegg home Books Study Textbook Solutions Expert Q&A Study Pack Practice Learn Writing Flashcards Math Solver Internships Scholarships Money
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Simplify cosx(tan^2x+1)=secx-Answer by jim_thompson5910 () ( Show Source ) You can put this solution on YOUR website!0 votes 1 answer Match the following (a) ∫log x dx (i) (x 1)^3/3 c (b) ∫ tan^3x dx, x∈π/2, π/2 (ii) π/4
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Tan^2 (x) WolframAlpha Volume of a cylinder?A) 10n= n b) 10n=n c) n n=10 d) 10n=0nTrigonometry Simplify sec (x)cos (x) sec(x)cos (x) sec ( x) cos ( x) Rewrite sec(x)cos(x) sec ( x) cos ( x) in terms of sines and cosines 1 cos(x) cos(x) 1 cos ( x) cos ( x) Cancel the common factors 1 1
CscX = 1 / sinX sinX = 1 / cscX secX = 1 / cosX cosX = 1 / secX tanX = 1 / cotX cotX = 1 / tanX tanX = sinX / cosX cotX = cosX / sinX Pythagorean Identities sin 2 X cos 2 X = 1 1 tan 2 X = sec 2 X 1 cot 2 X = csc 2 X Negative Angle IdentitiesCosx/(secx1) cosx/(tan^2x) = cot^2x Answers 3 Show answers Another question on Mathematics Mathematics, 1930 15 pointsfind the least common multiple of the expressions 1 3x^2, 6x 18 2 5x, 5x(x 2) 3 x^2 9, x 3 4 x^2 3xThis question was just answered and I'm not sure if this is the same person or not If so, please let me know where you're stuck and what part (s) do not make sense to you Thanks cosx (tan^2x1)=secx cosx*tan^2xcosx=secx
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Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreTan(x y) = (tan x tan y) / (1 tan x tan y) sin(2x) = 2 sin x cos x cos(2x) = cos ^2 (x) sin ^2 (x) = 2 cos ^2 (x) 1 = 1 2 sin ^2 (x) tan(2x) = 2 tan(x) / (1Prove (1cosx)/ (1cosx)=tan^2 (x/2) Trigonometric Identities Symbolab Identities Pythagorean Angle Sum/Difference Double Angle Multiple Angle
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(cosx)(tan^2x) cosx = cosx(tan^2x1) = (cosx)(sec^2x) = cosx/cos^2x = 1/cosx = secxProve the identity cosx(1tan^2x)=secx Answers 2 Show answers Other questions on the subject Mathematics Mathematics, 1550, winterblanco Which of the following is the equation that says that the product of a number and ten is equal to percent of that number ?Haciéndolo se obtiene tan 2 x ( sec x − 1) ( sec x 1)( sec x − 1) 1 = sec x efectuando solamente las multiplicaciones del denominador, por tratarse de los dos binomios conjugados que interesan tan 2 x ( sec x − 1) sec 2 x − 1 1 = sec x por la fórmula (102) , sustituyendo en el denominador el valor de sec 2 x − 1
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//googl/JQ8NysVerifying a Trigonometric Identity (cos(x) 1)/tan^2(x) = cos(x)/(sec(x) 1)Tan(3x) 1 = sec(3x) Thanks, pretend 3x equals x so tanx 1 = secx we know the law that 1 tanx = secx so tanx 1 becomes secx and secx = secx sec(3x) = sec(3x) just put 3x back in for x you don't really have to change 3x to x but it kinda makesTan(x y) = (tan x tan y) / (1 tan x tan y) sen(2x) = 2 sen x cos x cos(2x) = cos ^2 (x) sen ^2 (x) = 2 cos ^2 (x) 1 = 1 2 sen ^2 (x) tan(2x) = 2 tan(x) / (1
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= 1Tan^2x(Cos^2xSin^2x) = 1Tan^2x1 = Tan^2x = Right hand side identity answered by david Expert (CosX)(SecX) = Cot^2(X) asked in TRIGONOMETRY by mathgirl Apprentice trigonometricidentities2sin^2x = 3sinx1 asked in TRIGONOMETRY by anonymous trigonometricidentities;LHS = 1/ (sec x tan x)1/cos x= sec x tan x/ (sec x tan x) (sec x tan x) 1/cos x= sec x tan x/ (sec 2 x tan 2 x) 1/cos x= sec x tan x sec x= tan xRHS = 1/cos x 1/ (sec x tan x)= 1/cos x (sec x tan x)/ (sec x tan x) (sec x tan x)= 1/cos x (sec x tan x)/ (sec 2 x tan 2 x)= sec x (sec x tan x)/115 profile Hussain514 Sec^2 x 1 = tan^2x Proof Sec^2x = 1 tan^2x 1/cos^2x = 1 sin^2x/cos^2x 1/cos^2x sin^2x/cos^2x = 1 Using common denominatorTan^2x sec^2x = 1, Answers Answer from burners Hey there ) tan²x sec²x = 1 or 1 tan²x = sec²x sin²x cos²x = 1 Divide the whole by cos²xAnswer to Integrate the trigonometric integral integral of sec^2(x)/(1tan(x)) dx evaluated
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Cos(2x) = cos 2 (x) – sin 2 (x) = 1 – 2 sin 2 (x) = 2 cos 2 (x) – 1 HalfAngle Identities The above identities can be restated by squaring each side and doubling all of the angle measures The results are as follows Affiliate Sum Identities Product Identities Affiliate You will be using all of these identities, or nearly so, forCosx/(secx1) cosx/(tan^2x) = cot^2x Answers 3 Show answers Another question on Mathematics Mathematics, 2147 Alex drew a circle with right triangle prq inscribed in it, as shown below the figure shows a circle with points p, q, and r on it forming an inscribed triangle side pq is a chord through the center and angle r is aSolution for Tan^2xsecx1=0 equation Simplifying Tan 2 x secx 1 = 0 Reorder the terms 1 an 2 xT cesx = 0 Solving 1 an 2 xT cesx = 0 Solving for variable 'a' Move all terms containing a to the left, all other terms to the right Add '1' to each side of the equation 1 an 2 xT 1 cesx = 0 1 Reorder the terms 1 1 an 2 xT cesx = 0 1 Combine like terms 1 1
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Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreHriman cosx secx − 1 − cosx tan2x = cot2x cosx secx − 1 − cosx sec2x − 1 = cot2x cosx secx − 1 − cosx (secx −1)(secx 1) = cot2x cosx(secx 1) (secx − 1)(secx 1) − cosx (secx −1)(secx 1) = cot2x 1 cosx (secx − 1)(secx 1) − cosx (secx −1)(secx 1) = cot2x 1 (secx − 1)(secx 1) = cot2x 1 sec2x −1 = cot2x1 cos ( x) 1 cos ( x) 1 cos(x) 1 cos ( x) Rewrite 1 cos(x) 1 cos ( x) as sec(x) sec ( x) sec(x) sec ( x) Because the two sides have been shown to be equivalent, the equation is an identity cos(x)sin(x)tan(x) = sec(x) cos ( x) sin ( x) tan ( x) = sec ( x) is an identity
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`(1tanx )^2 (1cotx )^2 ` `= 12tanxtan^2x12cotxcot^2x` `= (1tan^2x)(1cot^2x)2(tanxcotx)` We know that;∫1/(sin x cos x) dx = (A) 1/2 log tan(x/2 π/8) k (B) log tan(x/2 π/8) k 1/2 log tan(x/2 π/8) k (D) None of these asked in Mathematics by Nakul01 (369k points) bseb model set;1 Answer Monzur R We have to use the common identity sin2x cos2x = 1 Dividing each term by cos2x, we get tan2x 1 = sec2x So cosx(tan2x 1) = cos(sec2x) = cosx 1 cos2x = 1 cosx = secx
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Please Subscribe here, thank you!!!In third quadrant, tanx and cotx are positive and sinx, cosx, secx and cosecx are negative We know that Question 4 Find the values of the other five trigonometric functions in each of the following sin in quatrant I (1 tan 2 x) tan 2 x = 1 tan 4 x 2 tan 2 x Tan 4 x tan 2 x = 1 tan 4 x 2 tan 2 x 3 tan 2 x = 1 tan x = 1Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more
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IF you recognize (from the fundamental identities) that sec^2 x 1 = tan^2 x, then working with the righthand side should be obvious Multply numerator and denominator of the righthand side by (sec x 1) cos x(sec x 1)(sec x 1)(sec x 1) cos x(sec x 1)sec^2 x 1 cos x(sec x 1)xxx tan^2 x OKnow we have the denominator we wantX2y< 3 xy> 4 3x2y> 4 Answers 2 continueAdvertisement Categories Algebra (112) Angle Between Two Lines (27) Arithmetic Calculation (2) Circle (19) Composite Functions (1) Compound Angles (40) Compound Interest (5) Computer (1) Conditional Trigonometric Identities (1) Coordinate Geometry () English (1) EPH (1) Equations (60) Factor Theorem (1) Geometry (21) HCF (15) Indices (42) LCM (15) MCQs (4) Mean Deviation
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In Trigonemetry Laws and Identities, there are some rule that we will use to prove 1 / sec² (x) = cos² (x) * tan² (x) 1 = sec² (x) * sin² (x) cos² (x) = 1 * tan (x) = sin (x) / cos (x) We will prove from the Left Hand Side We know that sec²Find an answer to your question 1tanx/sinx 1cotx/cosx = 2(secxCosecx) TayJoker4292 TayJoker4292 Math Secondary School answered 1tanx/sinx 1cotx/cosx = 2(secxCosecx) 1 See answer TayJoker4292 is waiting for1tan^2x=sec^2x Change to sines and cosines then simplify 1tan^2x=1(sin^2x)/cos^2x =(cos^2xsin^2x)/cos^2x but cos^2xsin^2x=1 we have1tan^2x=1/cos^2x=sec^2x Trigonometry Science The correct identities are 1 tan^2x = sec^2x 1 cot^2x = csc^2x sin^2x cos^2x = 1 which correspond to B and D thank you!!!Tanx = t Sec^2 x dx= dt So now it is, 1/ (1t)^2 dt This integral is given by 1/1t and t= tanx So, it is cosx/cosx sinx tanx = t Sec^2 x dx= dt So now it is, 1/ (1t)^2 dt This integral is given by 1
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